Calculating Electron Velocity and Orbit in Crossed Electric and Magnetic Fields

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The velocity of a beam of electrons passing through crossed electric and magnetic fields of 6.8 kV/m and 4.9 mT is calculated using the formula v = E/B, resulting in a velocity of approximately 1.3877 x 10^6 m/s. To determine the radius of the electron's orbit when the electric field is turned off, the relevant equations involve the magnetic force acting as the centripetal force for circular motion. The discussion highlights confusion regarding the appropriate equations to use for calculating the radius. Understanding the relationship between magnetic force and centripetal force is crucial for solving this part of the problem. The conversation emphasizes the importance of applying the correct physics principles to find the solution.
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Homework Statement



What is the velocity of a beam of electrons that go undeflected when passing through crossed electric and magnetic fields of magnitude 6.8 kV/m and 4.9 mT, respectively?

What would be the radius of the electron's orbit if the electric field were turned off?

Homework Equations



v = E/B

The Attempt at a Solution



I got the first part by using the equation above. (I converted the measurements because I'm looking for m/s). So 6.8 kV/m is 6800 V/m and 4.9 mT is .0049T.

v = E/B
v = (6800V/m)/(.0049T)
v = 1.3877*10^6 m/s

For the second part, I am a bit confused as to how to find the radius (which equation to use?).
 
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What force acts on a charged particle in magnetic field? That force provides the centripetal force for the circular motion.
 
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