Calculating Elevator Motor Work: 500 kg Lifted 50 m | Urgent Problem Solution

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To calculate the work done by an elevator motor lifting a 500 kg elevator 50 m, the formula W = F.S is used, where F is the force and S is the displacement. The force required is equal to the weight of the elevator, calculated as mg, where m is mass and g is gravitational acceleration. The angle between the force and displacement should be 0 degrees, not 90 degrees, since both are in the same direction (upwards). Therefore, the correct calculation is W = mg x 50 m. Assuming no acceleration, this approach accurately determines the work done by the motor.
dsptl
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How much work does an elevator motor do to lift a 500 kg elevator a height of 50 m?

attempt: W = F.S.Cos90 = 0 J

but i think its not right... Please help some1?
 
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dsptl said:
How much work does an elevator motor do to lift a 500 kg elevator a height of 50 m?

attempt: W = F.S.Cos90 = 0 J

but i think its not right... Please help some1?
Why is the angle between the force and the displacement 90o?
 
is tht suppose to be 0 then?
 
dsptl said:
is tht suppose to be 0 then?
Well, in which direction is the force applied? And in which direction is the elevator moving?
 
upwards...

so is tht going to something like W = mg x 50m x cos0
 
dsptl said:
upwards...

so is tht going to something like W = mg x 50m x cos0
Assuming that the elevator does not accelerate, that would be correct.
 
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