Calculating expected values for a random variable with a continuous distribution

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To calculate E(e^(ax)) for a random variable X with the density f(x)=e^(-2|x|), it is necessary to consider the integral over the entire real line, from -Infinity to Infinity. The function |x| is not integrable as a single definition across the entire range, so it should be broken into two parts: one for x >= 0 and another for x < 0. This approach allows for a completely integrable function over the associated domains. It is essential to solve the expectation separately for these two cases of x to obtain accurate results. This method ensures proper handling of the continuous distribution's characteristics.
Halen
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X is a random variable with a continuous distribution with density f(x)=e^(-2|x|), x e R
How would you calculate E(e^(ax)) for a e R?

Will it be right to take a certain range of a?
And also, can you take the bounds for the integral to be between -Infinity and Infinity?
 
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Halen said:
X is a random variable with a continuous distribution with density f(x)=e^(-2|x|), x e R
How would you calculate E(e^(ax)) for a e R?

Will it be right to take a certain range of a?
And also, can you take the bounds for the integral to be between -Infinity and Infinity?

|x| is not integrable over the whole range with a single definition. It is C0 continuous but you can't differentiate it and get a continuous function over the interval of the reals.

If you want to find the expectation break it up into parts where you have a completely integrable function over the associated domain.

As you know |x| = x if x >= 0 and -x if x < 0. That should hopefully give you a head start.
 
Thank you! Helps indeed!
So do you suggest that i solve it separately for the two cases of x?
 
Yes you will have to do that.
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
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