Calculating expected values for a random variable with a continuous distribution

Halen
Messages
13
Reaction score
0
X is a random variable with a continuous distribution with density f(x)=e^(-2|x|), x e R
How would you calculate E(e^(ax)) for a e R?

Will it be right to take a certain range of a?
And also, can you take the bounds for the integral to be between -Infinity and Infinity?
 
Physics news on Phys.org
Halen said:
X is a random variable with a continuous distribution with density f(x)=e^(-2|x|), x e R
How would you calculate E(e^(ax)) for a e R?

Will it be right to take a certain range of a?
And also, can you take the bounds for the integral to be between -Infinity and Infinity?

|x| is not integrable over the whole range with a single definition. It is C0 continuous but you can't differentiate it and get a continuous function over the interval of the reals.

If you want to find the expectation break it up into parts where you have a completely integrable function over the associated domain.

As you know |x| = x if x >= 0 and -x if x < 0. That should hopefully give you a head start.
 
Thank you! Helps indeed!
So do you suggest that i solve it separately for the two cases of x?
 
Yes you will have to do that.
 
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Back
Top