Chemistry Calculating Fe2O3 Reactivity with Fe

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To calculate the grams of Fe2O3 needed to react with 0.57 mol of Fe, first determine the moles of Fe2O3 required using the stoichiometry of the reaction, which shows that 2 moles of Fe are produced from 1 mole of Fe2O3. Therefore, 0.57 mol of Fe corresponds to 0.285 mol of Fe2O3. Next, convert moles of Fe2O3 to grams using its molar mass, which is approximately 159.69 g/mol. Multiplying 0.285 mol by the molar mass yields about 45.5 grams of Fe2O3 needed for the reaction. This calculation is essential for understanding the reactivity of Fe2O3 with Fe in chemical processes.
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How can you calculate how many grams of Fe2O3 must react with 0.57 mol of Fe when given the formula:
Fe2O3 + 3CO = = = => 2Fe + 3CO2
 
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toughguy said:
How can you calculate how many grams of Fe2O3 must react with 0.57 mol of Fe when given the formula:
Fe2O3 + 3CO = = = => 2Fe + 3CO2
Have you any thoughts of your own?
 
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