Calculating Final Speed in Elastic collision (momentum)

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SUMMARY

The discussion focuses on calculating final velocities after an elastic collision using the law of conservation of momentum and energy. Given two balls with masses M = 50 kg and m = 100 kg, and initial velocities u1 = 20 m/s and v1 = 10 m/s, the momentum equation is established as m*v1 + M*u1 = m*v2 + M*u2. Participants emphasize that both momentum and kinetic energy are conserved in elastic collisions, necessitating a second equation to solve for the final velocities.

PREREQUISITES
  • Understanding of conservation laws in physics, specifically momentum and energy conservation.
  • Familiarity with basic algebra for solving equations.
  • Knowledge of elastic and inelastic collision concepts.
  • Ability to manipulate equations involving multiple variables.
NEXT STEPS
  • Study the derivation of the conservation of momentum equation in elastic collisions.
  • Learn how to apply the conservation of kinetic energy in elastic collisions.
  • Explore examples of one-dimensional elastic collisions with varying masses and velocities.
  • Investigate the differences between elastic and inelastic collisions in detail.
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Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding collision dynamics and conservation laws.

Mushroom79
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Homework Statement



If it is eg. two balls, both going to the right before and after an elastic shock, how do you determine their velocities after the collision? (speeds before and weights are given)

Eg.

M = 50 kg
u1 = 20 m / sm = 100 kg
v1 = 10 m / s

(M, m = mass)
(u1, v1 = velocity before the collision)
(u2, v2 = velocity after collision)

Homework Equations



The law of conservation of momentum:
m*v1+M*u1= m+M*v2*u2

Momentum before = Momentum after

The Attempt at a Solution



m*v1+M*u1= m+M*v2*u2 →

100 * 10 +50 * 20 = 100 +50 * v2 * u2

How do I continue from here?
 
Last edited:
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In elastic collisions energy is also conserved , so you can set up one more equation .
 
ZxcvbnM2000 said:
In elastic collisions energy is also conserved , so you can set up one more equation .

Oh, right. Think "momentum before equals momentum after" is what you meant.
Forgot to put it there.
 
In elastic collisions :

Momentum is conserved

Energy Is conserved
In inelastic collisions:

Momentum Is conserved

Energy is not conserved

Just to be more clear :P
 

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