Calculating Force from Stopping in Gravity: Help Appreciated

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To calculate the force generated when stopping an object moving towards Earth, the acceleration due to gravity must be considered alongside the object's motion. The initial velocity (vi) is 0.6 m/s, and the final velocity (vf) is 0, with a time (t) of 0.1 seconds. The equation a = (vf - vi) / t can be used to find acceleration, but the net force (f = ma) must account for both gravitational force and the force applied to stop the object. It's important to identify all forces acting on the object, including gravity, to accurately determine the net force. Understanding these components is crucial for a proper calculation.
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Hi
I am trying to roughly calculate a force.
If i am moving an object towards the Earth and then stop it, how much force will this generate?
a=vf-vi/t
- vi =0.6m/s
-vf= 0
-t = 0.1 s

This equalling - a

Then applying f=ma
m=150kg

Im unsure how to add gravity into this.

would...
0-(9.8+0.6)/0.1 be a good way to estimate this?

Any help is appreciated.
Thanks in advance[Moderator's note: Moved from a technical forum and thus no template.]
 
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No. The units of grand v are not the same anyway.
Presumably the object is freely falling and you apply an upward force to stop it when it reaches a speed of 0.6 m/s. You want to know that force.
In your equation f = ma, f is actually the net force and consists of more than one force acting on it. Can you identify these forces?
 
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