Calculating Forces in a Rotational System with a Wrecking Ball and Boom

AI Thread Summary
To calculate the forces in the rotational system involving the wrecking ball and boom, it's essential to identify an appropriate pivot point, typically at the base of the boom. The weight of the wrecking ball (5400 N) and the boom (3800 N) must be considered along with the angles of the support cable (32°) and the boom (48°). The equation L(5400) - Lsin(32)FT + 1/2Lsin(48)3800=0 can be used to find the tension in the cable (FT), but the length (L) can be canceled out since it appears in all terms. It's crucial to ensure the correct application of torque and forces to achieve the desired solution. Properly setting up the equations will lead to the correct calculation of the cable forces.
smith5029
Messages
8
Reaction score
0
A wrecking ball (weight = 5400 N) is supported by a boom, which may be assumed to be uniform and has a weight of 3800 N. As the drawing shows, a support cable runs from the top of the boom to the tractor. The angle between the support cable and the horizontal is 32°, and the angle between the boom and the horizontal is 48°.

i'm drawing a blank really, i don't know what to use as my pivot point.
i had L(5400) - Lsin(32)FT + 1/2Lsin(48)3800=0
then i solved for FT but it was wrong, can you help me, or show me where to go
 
Physics news on Phys.org
the question wants to know what the force of the cables question is, and the length isn't defined but you can cancel it out right?
 
You posted in college help already. Don't double post.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top