Calculating Frictional Force: Solving for u in a Horizontal Curve | Physics Help

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To calculate the frictional force required to keep a 49.2 kg car moving at 12.6 m/s around a curve with a radius of 31.3 m, the net forces must be analyzed. The normal force (N) equals the weight (mg), and the frictional force (fs) is given by the equation fs = m(v^2/r). Substituting N into the equation leads to u x mg = m(v^2/r), where u represents the coefficient of friction. The calculation yields a value of 0.517, but the question specifically asks for the frictional force, not the coefficient. Understanding the distinction between these terms is crucial for solving the problem correctly.
mixedtape_15
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I really am not getting this physics stuff...again I thought I had this one figured out but it doesn't seem to be right.
So the question...
A 49.2 kg car is moving at 12.6 m/s around a horizontal curve whose radius is 31.3 m. What is the magnitude of the fictional force required to keep the car from sliding?

and this is what I did..
I found my net force for x and y
Fy = may
Fy = 0
N- W = 0
N = mg

Fx = max
fs = max
u x N = m(v^2/r)

so then I substituted in my N and got
u x mg = m(v^2/r)

and I solved for u (frictional force...I'm just using u for the term)

u x (49.2kg)(9.81m/s^2) = (49.2kg)(12.6^2/31.3m)

and it works out to be 0.517 and the computer is telling me I'm wrong once again. so I must be wrong.
 
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The question does not ask you to find μ. It asks you for the frictional force.
 
Thank you! I have some serious problems with reading these things wrong.
 
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