Calculating Gravity of a Single Body: Equation and Explanation

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The equation for calculating the gravitational field strength of a single body is expressed as GM/r, where G is the gravitational constant, M is the mass of the body, and r is the distance from the center. Gravity is indeed stronger closer to the center of a massive body, but as one approaches the center of the Earth, the gravitational force decreases to zero. This decrease in gravity is due to the assumption in Newtonian gravity that all mass is concentrated at the center, which only holds true outside the body. For a uniform spherical mass distribution, specific equations apply for regions inside and outside the body. Understanding these principles is crucial for accurately calculating gravitational effects.
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Sorry to ask such a simple question but I appreciate the level of knowldege you guys have.
What is the equation for calculating a single bodies gravity?
 
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The gravitational field strength is = GM/r
(in classical gravity - it's a bit more complicated in general relativity)

It's really just a different way of writing the equation in the other thread for the force on a 1kg object placed at a distance 'r'
 
Is r measured from the centre of the object? If so is gravity stronger closer to the centre of the earth.
Thanks by the way
Chris
 
Yes The nice thing about Newton's gravity is you can just use the total mass at the 'centre of gravity' and not have to care about the shape or distribution.
The Earth could actually be hollow and as long as it had the same total mass you wouldn't be able to tell - gravity would work just the same.
 
So at the centre of an object the value r = 0
 
While in Newtonian gravity you treat all an object's mass as if it were located at the center, this assumption is only valid while you are outside of the body. If, for example, you started digging into the earth, you would find that the gravitational force decreases to zero as you approach the center.
 
Is there an equation tht reflects this?
 
Nabeshin said:
While in Newtonian gravity you treat all an object's mass as if it were located at the center, this assumption is only valid while you are outside of the body.
Furthermore, it's only valid for spherically symmetric mass distributions.
 
chis said:
Is there an equation tht reflects this?

Assuming a uniform spherical mass distribution, we have the following equations:

g(r)=-G\frac{m}{r^{2}}\hat{r} ; r>r_{0}
g(r)=-\frac{Gm_{0}}{r_{0}^{3}}r\hat{r} ; r<r_{0}
 

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