Calculating Gravity on the Surface of Asteroid Ceres | Forces Homework Help

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To calculate the gravity on the surface of the asteroid Ceres, the gravitational acceleration formula g = G*M/r^2 is used, where G is the gravitational constant, M is the mass of Ceres, and r is its radius. The mass of Ceres is given as 7x10^20 kg and the radius as 500 km. An astronaut weighing 85 kg on Earth would weigh significantly less on Ceres due to its lower gravity. The discussion emphasizes the importance of correctly applying the gravitational equations to find both the gravitational acceleration and the weight of the astronaut on Ceres. Overall, understanding the relationship between mass, gravity, and weight is crucial for solving the problem.
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Homework Statement



The asteroid Ceres has a mass of 7x10^20 and a radius of 500km

a. what is the gravity on the surface
b. How much would a 85kg astronaut weigh in ceres

Homework Equations



Fg = (Gm1m2)/r^2

The Attempt at a Solution



None, where do I get the seccond mass value from? or am I using the wrong equation?

pls help, all constructive input appreciated :)
 
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Well, you can use that equation, but you'll need another one: F = mg. You might have seen this before with w (for "weight") in place of F, but it's the same thing. Part (a) is just asking for the value of g, the gravitational acceleration.

Can you see how to put this equation together with the one you have to find g?
 
So something like

w=mg
w=(7.20x10^20)(6.67x10^-11)
w=4.669x10^10

then

fg=(Gm1m2)/r^2
fg=(6.67x10^-11)(4.669x10^10)(7.20x10^20)/500^2
fg=2.24x10^21

like that?
 
In figuring gravity for Ceres, the mass of the object that you want to determine the value of gravity for drops out.

W = m*g = G*M*m/r2

g = G*M/r2

To find W then

W = m*g
 
7m-84 said:
So something like

w=mg
w=(7.20x10^20)(6.67x10^-11)
w=4.669x10^10

then

fg=(Gm1m2)/r^2
fg=(6.67x10^-11)(4.669x10^10)(7.20x10^20)/500^2
fg=2.24x10^21

like that?
No, not that... putting equations together is not the same thing as plugging in numbers. I was trying to point you towards the answer LowlyPion wrote out.
 
got it
 
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