Calculating Gravity on the Surface of Asteroid Ceres | Forces Homework Help

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Homework Help Overview

The discussion revolves around calculating the gravitational acceleration on the surface of the asteroid Ceres, given its mass and radius. Participants are exploring the application of gravitational equations to determine the weight of an astronaut on Ceres.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster questions the need for a second mass value and the appropriateness of the gravitational equation being used. Some participants suggest using the equation for weight in conjunction with the gravitational formula to find gravitational acceleration.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on how to combine equations to find gravitational acceleration. There is a mix of attempts to substitute values into equations and clarifications on the relationships between the variables involved.

Contextual Notes

There is an indication of confusion regarding the application of the gravitational equations and the necessary values to use, particularly concerning the second mass in the gravitational formula.

7m-84
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Homework Statement



The asteroid Ceres has a mass of 7x10^20 and a radius of 500km

a. what is the gravity on the surface
b. How much would a 85kg astronaut weigh in ceres

Homework Equations



Fg = (Gm1m2)/r^2

The Attempt at a Solution



None, where do I get the seccond mass value from? or am I using the wrong equation?

pls help, all constructive input appreciated :)
 
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Well, you can use that equation, but you'll need another one: F = mg. You might have seen this before with w (for "weight") in place of F, but it's the same thing. Part (a) is just asking for the value of g, the gravitational acceleration.

Can you see how to put this equation together with the one you have to find g?
 
So something like

w=mg
w=(7.20x10^20)(6.67x10^-11)
w=4.669x10^10

then

fg=(Gm1m2)/r^2
fg=(6.67x10^-11)(4.669x10^10)(7.20x10^20)/500^2
fg=2.24x10^21

like that?
 
In figuring gravity for Ceres, the mass of the object that you want to determine the value of gravity for drops out.

W = m*g = G*M*m/r2

g = G*M/r2

To find W then

W = m*g
 
7m-84 said:
So something like

w=mg
w=(7.20x10^20)(6.67x10^-11)
w=4.669x10^10

then

fg=(Gm1m2)/r^2
fg=(6.67x10^-11)(4.669x10^10)(7.20x10^20)/500^2
fg=2.24x10^21

like that?
No, not that... putting equations together is not the same thing as plugging in numbers. I was trying to point you towards the answer LowlyPion wrote out.
 
got it
 

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