Calculating Heat of Formation for NH4Cl Using Calorimetry

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To calculate the heat of formation for NH4Cl using calorimetry, the reactions for both parts of the experiment must be clearly defined. The first reaction involves the mixing of NH3(aq) and HCl(aq) to form NH4Cl(aq), while the second reaction involves the dissolution of solid NH4Cl in water. The temperature changes (deltaT) observed in both experiments are crucial for determining the enthalpy change (deltaH) per mole for each reaction. It is important to consider the heat capacity of the NH4Cl solution for accurate calculations, although assuming the heat capacity of pure water can simplify the process. Understanding these components is essential for calculating the heat of formation accurately.
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Homework Statement


i did a lab calorimeter lab with 50ml 1.51M nh3 and 50ml 1.59M hcl yeilding nh4cl (aq)
the deltaT was 8.6 degC
second part is 100ml of h2o and 4.082g nh4cl
deltaT was -2.8 degC

Homework Equations


how do i find deltaH per mole for each reaction?

The Attempt at a Solution

 
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Hint: Write out the reactions for the first part and the second part. What form was the ammonia? Was it aqueous? How should that be written?
 
its nh3(aq) + hclz(aq) = nh4cl(aq)
and nh4cl(s) = nh4cl(aq)

but where do i go from there?
 
NH3 in water is NH4+ OH-
HCl in water is H3O+ Cl-

one of the two reactions is:

NH4+(aq) + Cl-(aq) ----> NH4Cl(aq)

Can you determine the other reaction?

You will need the heat capacity of the ammonium chloride solution. Can you determine what the concentration will be?
Alternatively, you could assume the heat capacity of pure water, but it won't be an exact solution. Can you think of why you need to obtain the heat capacity?
 
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