Calculating Heat Required to Heat Water from 15.5°C to 85°C

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To calculate the heat required to raise the temperature of 90g of water from 15.5°C to 85°C, the formula QH2O = mH2O * cH2O * ΔTH2O is used, where ΔTH2O is the temperature change. The specific heat of water is 1 cal/g°C, making the calculation straightforward for the water alone. However, the discussion raises the concern of the aluminum vessel's mass (178g) and its specific heat, suggesting that the heat required to warm the vessel should also be considered in the total calculation. This highlights the importance of accounting for both the water and the vessel when determining the total heat needed. Overall, the solution must incorporate both components for an accurate result.
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Homework Statement



An aluminum vessel hose mass is 178g contains 90g of water at 15.5°C. How many calories of heat are required to bring the water to a final temperature of 85°C? The specific heat of water is 1cal/g°C.

Given:
mAl=178g
mH2O=90g
T1=15.5°C
T2=85°C
cH2O=1cal/g°C

Homework Equations


Im planning to use this formula for heat quantity

QH2O=mH2OcH2OΔTH2O


The Attempt at a Solution

 
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kimkibun said:

Homework Statement



An aluminum vessel hose mass is 178g contains 90g of water at 15.5°C. How many calories of heat are required to bring the water to a final temperature of 85°C? The specific heat of water is 1cal/g°C.

Given:
mAl=178g
mH2O=90g
T1=15.5°C
T2=85°C
cH2O=1cal/g°C

Homework Equations


Im planning to use this formula for heat quantity

QH2O=mH2OcH2OΔTH2O


The Attempt at a Solution


What about the aluminum vessel? How can you heat the water without also heating the vessel?
 

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