Calculating heat transfer coefficient from experimental data

In summary, this graph shows the rate of cooling of a tent from about 35 degrees Celsius to 15 degrees Celsius. The tent appears to cool at a linear rate, and the convective heat transfer coefficient is approximately 0.5 W/m2.
  • #1
Jakob81
4
0
I have a graph which shows the rate of cooling of a tent from about 35 deg C to 15 deg C, it looks like this:

http://students.bath.ac.uk/en0jma/graph.gif

How do I work out the convective heat transfer coefficient of the tent from this data?

Thanks for any help
 
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  • #2
Is this free convection or forced convection? What is your experimental set up?
 
  • #3
this is free convection.

The tent was heated up, and then allowed to cool naturally. The graph is the results of the thermometer readings taken from within the tent.

Ive been working out the reduction in energy of the air between two temperatures, say 34 and 20, and then dividing by the time taken to reduce heat, this gives X watts of heat (Q)

i know I should be using the equation

Q = hA(delta T)

to try and work out h, but I am not sure if I am using the right values for delta T, already know A, the area of the tent walls.

I want to find h, the convective heat transfer coefficient by re-arranging the above to,

h = Q / A(delta T)
 
  • #4
You are doing it the way I would. In the beginning, when the slope of your graph is near linear, is probably the best place to calculate a Q and a delta-T to plug into the Q=hA(delta-T) equation - say, the first 100 seconds. Otherwise, you are averaging the slope (and Q) over a non-linear period using a linear equation.

To check, plug your numbers back into the equation you've built and see if Excel generates the same graph as your experimental data.
 
  • #5
My 2 cents worth here...

I would pretty much do it the same way, but if I were going to use this number in any kind of calculation, I'd extend the time frame of interest to a point that appears to become asymtotic to [tex]T_{\infty}[/tex] and curve fit a straight line there. That way you will get a bit more conservative average heat transfer coefficient that is a bit more representative over the broader temperature range. That is my opinion though.

If you're not going to do that then I'd do it in the linear portion like Russ mentioned.
 
  • #6
Cheers, that's exactly what I've done, and it seems to work! Thanks very much for the help. :smile:
 
  • #7
Hi, i think am having the same issue as the guy above, except I'm not sure how to calculate the Q value needed to find heat transfer coefficient. Thanks.
 

1. What is the heat transfer coefficient?

The heat transfer coefficient is a measure of how well heat is transferred between two mediums, such as a solid object and a fluid. It represents the rate of heat transfer per unit area per unit temperature difference between the two mediums.

2. How is the heat transfer coefficient calculated?

The heat transfer coefficient can be calculated by dividing the heat transfer rate by the product of the surface area and the temperature difference between the two mediums. It can also be determined experimentally by measuring the temperature difference and heat flux across a surface.

3. What are the units of heat transfer coefficient?

The units of heat transfer coefficient depend on the system of measurement being used. In SI units, it is measured in watts per square meter per degree Celsius (W/m²·°C). In imperial units, it is measured in British thermal units per hour per square foot per degree Fahrenheit (BTU/hr·ft²·°F).

4. How does the heat transfer coefficient vary in different materials?

The heat transfer coefficient depends on several factors, including the properties of the materials involved, the surface roughness, and the flow characteristics of the fluid. In general, materials with higher thermal conductivity will have a higher heat transfer coefficient, as heat can be transferred more easily through them.

5. Can the heat transfer coefficient be used to predict heat transfer in a system?

While the heat transfer coefficient is an important factor in determining heat transfer rates, it is not the only factor. Other variables, such as the temperature difference, surface area, and thermal properties of the materials, also play a role. Therefore, the heat transfer coefficient alone cannot accurately predict heat transfer in a system, but it can provide useful information in conjunction with other data.

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