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foreverconfused
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1.Problem The problem is: calculate the horizontal distance the ball will travel if the same spring is aimed 25° from the horizontal. This is the second part.
The first part was: a small steel ball bearing with a mass of 21 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.33 m. Calculate the speed at which the ball leaves the spring (my correct answer was 5.11 m/s)2.Relevant equations: Just like the first part I tried using v2=v02+2ax since that still seems relevant. I know I should be incorporating Vx=Vcosθ but I'm not sure how. 3.The attempt at a solution: I set the final velocity to zero and the initial velocity as the answer I had gotten from part one. I set the gravity as acceleration as I had in part one and solved for x (displacement).
0=5.112+2*9.81*x
then x=1.15 m which I know isn't right.
The answer is 2.04 m, I just don't know how to get that.
Also this is my first post so please let me know if I'm missing any information.
The first part was: a small steel ball bearing with a mass of 21 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.33 m. Calculate the speed at which the ball leaves the spring (my correct answer was 5.11 m/s)2.Relevant equations: Just like the first part I tried using v2=v02+2ax since that still seems relevant. I know I should be incorporating Vx=Vcosθ but I'm not sure how. 3.The attempt at a solution: I set the final velocity to zero and the initial velocity as the answer I had gotten from part one. I set the gravity as acceleration as I had in part one and solved for x (displacement).
0=5.112+2*9.81*x
then x=1.15 m which I know isn't right.
The answer is 2.04 m, I just don't know how to get that.
Also this is my first post so please let me know if I'm missing any information.
