Calculating if a Convertible Gets Wet from Dropped Bucket

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To determine if the convertible gets wet, the time it takes for the car to reach the parking garage entrance must be calculated alongside the time it takes for the bucket to fall. The convertible is traveling at 6.67 m/s and is 12 m away from the entrance, which means it will take approximately 1.8 seconds to reach the entrance. The height from which the bucket is dropped is crucial for calculating its fall time, as it influences whether the bucket hits the car before it arrives. By establishing the height as a variable, one can analyze the dynamics of both the falling bucket and the approaching car. Ultimately, without the initial height of the bucket, the conclusion about whether the car gets wet remains uncertain.
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A convertible with the top down is heading for a parking garage entrance at a steady 24 km/h. Directly above this entrance is a window washer who accidentally drops her bucket of water off her rising platform. At this time the car was 12 m from the entrance and the platform was traveling up at a speed of 1 m/s. Calculate if the car gets wet.

Okay, so here is my given information:

CONVERTIBLE:
V(const) = 24 km/h = 6.67 m/s
d = 12 m

WINDOW WASHER
V(initial) = -1.5 m/s

I really don't see where to begin. I know I can determine the time it will take for the convertible to reach the entrance of the garage, but I don't see what good that would do since I do not have the height above the road the window washer is when the bucket falls.

Help.
 
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By the way, this is not a kinematics problem. It is a dynamics problem.

Obviously, you need the initial height but if the problem is as you stated then you will take the height, say h, to be a parameter in your analysis.

I think the most direct approach would be to simply determine how long it takes for the bucket to hit the ground (in general this would really be the height of the car). Then calculate where the car would be at that time.
 
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