Calculating Inclination of an Air Hockey Table

AI Thread Summary
The discussion focuses on a physics problem involving the calculation of the inclination of an air hockey table based on the puck's motion. A student observes that a puck, initially given a velocity of 3.86 m/s, drifts 2.40 cm to the right while maintaining its speed along the table's length. The student correctly identifies that the table is not level and attempts to relate the forces acting on the puck to its motion. The net force acting on the puck is attributed to gravity, which influences its lateral drift without affecting its constant velocity along the table. The conversation highlights the relationship between gravity, inclination, and motion on a frictionless surface.
Aiko
Messages
8
Reaction score
0

Homework Statement


A physics student playing with an air hockey table (a frictionless surface) finds that if she gives the puck a velocity of 3.86 m/s along the length ( 1.79 m) of the table at one end, by the time it has reached the other end the puck has drifted a distance 2.40 cm to the right but still has a velocity component along the length of 3.86 m/s. She concludes correctly that the table is not level and correctly calculates its inclination from the above information.


Homework Equations





The Attempt at a Solution


I don't know how to relate velocity to force. The velocity is constant so all net force equations equal to zero. I have no clue how to really start.
 
Physics news on Phys.org
No there is a net force which pulls the puck to the right as it reaches the end of the table. The reason why the net force (gravity) doesn't affect the velocity of the puck is because it acts sideways to the velocity of travel of the puck, much like in circular motion.
 
Defennder said:
No there is a net force which pulls the puck to the right as it reaches the end of the table. The reason why the net force (gravity) doesn't affect the velocity of the puck is because it acts sideways to the velocity of travel of the puck, much like in circular motion.

If I set the coordinate system on the puck (which is on an incline plane), the force of gravity would be the only force acting on it in the x-direction, thus why it moves. Would it equal to zero or ma? It has a constant velocity in one direction.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top