Calculating Jet Size & True Length from Redshift & Hubble Constant

  • Thread starter Thread starter wolfpack693
  • Start date Start date
  • Tags Tags
    Jets
AI Thread Summary
To calculate the size of a quasar jet from a redshift of 0.158 and a Hubble constant of 65 km/s/Mpc, one must first convert the angular measure of 15 arc seconds into a physical distance using appropriate cosmological formulas. The second part requires determining the true length of the jet in light years, factoring in its angle of 6 degrees relative to the line of sight. Participants emphasize the importance of showing preliminary work to facilitate assistance with homework questions. Understanding the relationship between redshift, angular size, and distance is crucial for these calculations. Clear steps and formulas are necessary to arrive at the correct answers.
wolfpack693
Messages
2
Reaction score
0
2 part question.

1st part: I am givin the redshift of a quasar is .158 and Hubble constant of 65km/s/Mpc. I am asked to find the size of the jet(ly) as projected on the sky which has an angular measure of 15 arc secs. I've looked up ways and on any formulas that could help me but haven't found anything. Does anyone know how to get the size (formula wise).

2nd part: What is the true length in light years if it is pointed along the line of sight but off at an angle of 6 degrees?

Now this part I don't understand where to start from.

Anything helps thanks.
 
Physics news on Phys.org
Welcome to PF. You need to show some work before we can help you with homework questions. What have you tried thus far?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top