Calculating Kinetic Energy of a Positron from Gamma Photon Interaction

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A gamma photon with a frequency of 5.49 x 10^20 Hz can create an electron-positron pair, but the initial calculations suggested insufficient energy. The correct formula for calculating the positron's kinetic energy (Ekp) is Ekp = hf - 2E - Eke, where hf is the photon energy, E is the rest energy of the electron, and Eke is the electron's kinetic energy. After correcting calculation errors, the positron's kinetic energy was determined to be approximately 8.00 x 10^-14 J. The discussion emphasizes the importance of accurate unit conversion and careful calculation in solving physics problems.
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Homework Statement



A gammaphoton with a frequency of 5,49*10^20 Hz passes by near a nucleus, and turns into a electron/positron pair. The electron has an kinetic energy of 1,20*10^-13 J. How much kinetic energi is in the posistron?(we can neglect the energyexchange with the nucleus)

The Attempt at a Solution



Ive tried to solve this using this formula but i get a negative answer:

hf=2E+Ekp+Eke => Ekp=hf-2E-Eke

Where Ekp is the kinetic energi of the positron, "hf" is the energy of the photon, "E" is the rest energy of the electron and "Eke" is the kinetic energy of the electron.

I get that Ekp=-1,64*10^-10 J. This isn't right?
 
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The formula is correct. You must've made a mistake in your calculation.
 
your mistake is in the Units ... 1 Joule is 1 kg m2/s2 , so your electron mass must be in kg.
 
As far as i can understand, the energy in the photon is not enough to create a electron/positron pair?

hf<2E

And therefore the problem doesn't have an answer?
 
johann1301 said:
As far as i can understand, the energy in the photon is not enough to create a electron/positron pair?

hf<2E

And therefore the problem doesn't have an answer?

You're wrong, the problem does have an answer, which I just found. So we can be sure the problem is correct.

Your equation is also correct, so the error must lie in your working.

Unless you show this working, in detail, no one can help you further.
 
Ekp=hf-2E-Eke

Ekp=6,63*(10^-34)Js*5,49*(10^20)Hz - 2*9,1094*(10^-31)kg*(3,00*(10^8)m/s)^2 - 1,20*(10^-13)J

Ekp=8,00178*10^-14J

I just kept entering the wrong exponent in C^2.

Thanks:)
 
johann1301 said:
Ekp=hf-2E-Eke

Ekp=6,63*(10^-34)Js*5,49*(10^20)Hz - 2*9,1094*(10^-31)kg*(3,00*(10^8)m/s)^2 - 1,20*(10^-13)J

Ekp=8,00178*10^-14J

I just kept entering the wrong exponent in C^2.

Thanks:)

What I got too.

Here's a tip: Google calculator is your friend. Take a look at this: https://www.google.com.sg/search?q=...+-+2*mass+of+electron*c^2+-+1.2E-13J&safe=off

Just enter your expression as a query next time and Google works everything out, physical constants, units, etc. all inclusive!
 
Thanks!
 
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