Calculating Land Area and Confidence Interval with Uncertainty Propagation

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Homework Statement



The area of a flat, rectangular parcel of land is computed from the measurement of the length of two
adjacent sides, X and Y. Measurements are made using a scaled chain accurate to within 0.5% over its
indicated length. The two sides are measured several times with the following results:

X = 556 m
Stdev =5.3 m
n = 8

Y = 222 m
stdev = 2.1 m
n = 7


Estimate the area of the land and state the confidence interval of that measurement at 95%.

Homework Equations



propagation of uncertainty formula


<br /> \delta z = \sqrt {\left( {\frac{{\partial z}}{{\partial x}}dx} \right)^2 + \left( {\frac{{\partial z}}{{\partial y}}dy} \right)^2 } <br />



The Attempt at a Solution



My issue here is how to account for the accuracy of the chain in the problem statement. I can easily find the values of X&Y at 95% confidence using the mean value and stdev and plug them into the uncertainty formula. What do I do with the 0.5%?
 
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It's not clear how the distribution for the scale looks like. If it's a Gaussian distribution with a standard deviation of 0.5 you can simply add that in quadrature. If it's a uniform distribution within +-0.5% it's messy.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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