Calculating Limiting Reactant & Theoretical Yield of NaCl2

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To determine the limiting reactant and theoretical yield of NaCl2 from 53.2g of sodium (Na) and 65.8g of chlorine (Cl), it is essential to calculate the number of moles of each reactant using their atomic weights. The mole ratios of the reactants are crucial for identifying the limiting reactant. The discussion highlights that NaCl2 is an unlikely species, suggesting a focus on NaCl instead. For synthesizing ammonia from 25.2g of nitrogen (N) and 8.42g of hydrogen (H), the same mole calculation approach applies. The number of moles of each reactant must be determined, and the required mole ratio for ammonia synthesis should be established to find the maximum amount of ammonia that can be produced. The conversation emphasizes the importance of understanding mole ratios in both reactions to accurately identify limiting reactants and calculate yields.
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if there is 53.2g of Na and 65.8g of Cl, what is the limiting reactant and Theoretical Yield of NaCl2?

what is the maximum amount of Ammoniac that can be synthesized from 25.2g of Nitrogen and 8.42g of Hydrogen?

need help in that... please...
 
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The specie of NaCl2 for your first reaction is unlikely.

In both reactions which you ask, the MOLE ratios of each reactant is necessary for you to find the limiting reactant. You find the number of moles using the atomic weight of the reacting element.

For "ammoniac", did you mean "ammonia"? How many moles Nitrogen in 25.2 grams? How many moles of Hydrogen in 8.42 grams of Hydrogen? What ratio of one to the other is necessary for a mole of ammonia?
 

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