Calculating Load on Pilot in Horizontal Curve Flight

AI Thread Summary
To calculate the load on a pilot during horizontal curve flight, the centripetal acceleration formula (v^2/r) is used to determine the horizontal force acting on the pilot. The pilot's weight (mg) acts vertically downward, creating two perpendicular force components. The total load on the pilot's seat is found by calculating the resultant of these two forces, which involves using the Pythagorean theorem. The correct approach leads to a total load of 0.80 kN. Understanding the interaction of these forces is crucial for accurate calculations in aviation dynamics.
Miri
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Homework Statement


An airplane flies through a horizontal curve at a speed of 250km/h (69.44m/s). Radius=0.7km or 700m
Find the load of the pilot on the seat if her mass is 67kg.


Homework Equations


centripetal acceleration=v^2/r
and then the solution times the mass of the pilot, but this gives me the wrong result. The result should be 0.80kN
 
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You've got the horizontal component of the force the captain exerts on the seat because of the rotation. There is also a vertical component of force due to the captains weight. I think you are supposed to add those two vectors and find the total magnitude of the force.
 
I don't get what you mean...Can you tell me the formulas which I have to use? What do you mean by the two components? The first one is the mass and the second one the radius or what? Thanks
 
When the car takes a turn you are thrown in the outward direction due to centrifugal force. Its magnitude is mv^2/r. Similarly the pilot experiences the centrifugal force which is horizontal and away from the center of the curved path. The weight of the pilot mg acts in the downward direction. The resultant of these two forces will be total load of the pilot on the seat.
 
so you mean that mv^2/r + mg=0.80kN ? But that's wrong...i'm sorry, but I just don't get it...
 
Miri said:
so you mean that mv^2/r + mg=0.80kN ? But that's wrong...i'm sorry, but I just don't get it...

mv^2/r and mg are perpendicular to each other. Therefore resultant force = sqrt[ (mv^2/r)^2 + (mg)^2]^1/2
 
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