Calculating Magnetic Flux in a Bent Square Loop with a Uniform Magnetic Field

AI Thread Summary
To calculate the magnetic flux through a bent square loop in a uniform magnetic field, the formula used is MF = AB cos θ. The dimensions of the loop are 13.5 cm by 13.5 cm, and the magnetic field strength is 0.463 T at an angle of 33°. The area of the loop is determined to be 0.135 m². The correct approach involves using the area and the angle of the magnetic field to find the flux, confirming that the initial confusion regarding the area and angle was resolved. The final calculation yields the magnetic flux through the loop.
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Magnetic flux...PLEASE HELP!

Homework Statement


A 13.5 cm × 13.5 cm square bent at a angle 90°. A uniform 0.463 T magnetic field points downward at θ=33° angle. What is the magnetic flux through the loop? (a=6.75 cm, b=13.5 cm, c=6.75 cm.)

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Homework Equations





The Attempt at a Solution


MF = AB cos theta
Would it just be (.135 * .135) * 0.463 cos 33
I am not sure which area and angle to use?
 
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nevermind got it
 

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