Calculating Magnetic Force on Bent Wire in a Magnetic Field

AI Thread Summary
To calculate the magnetic force on a bent wire in a magnetic field, the current through the wire is determined to be 64.78 Amps using the formula I = V/R. The magnetic field strength is given as B = 1.4T, and the wire section is bent into a 60-degree arc. The challenge lies in correctly applying the formula F = I*l*B*sin(Phi) to find the magnetic force, particularly in understanding how to incorporate the angle of the arc. Clarification on the relationship between the magnetic field and the arc's bisector is needed for accurate calculations. This discussion highlights the importance of grasping the underlying concepts before proceeding with the homework.
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Homework Statement


A wire of length 95m and a diameter of 2.4mm has a total resistance 1.59Ohms. The potential difference between the ends of the wire is 103volts. A section of the wire 15.5cm in length is bent into an arc of 60deg. The magnetic field is parallel to the bisector of the arc and has a strength of B=1.4T . What is the magnitude of the magnetic force on the arc of wire?


Homework Equations


F = I*l*B*sin(Phi)


The Attempt at a Solution


parallel.jpg


I found the current by solving I = V/R which gives me 64.78 Amps.

Now the part I'm having trouble with is finding out the magnetic field that is parallel to the bisector of the arc. I don't think I understand this question The magnetic field is parallel to the bisector of the arc and has a strength of B=1.4T .

What are your suggestion on this one? And fyi, my teacher didn't lecture this topic yet, but the reason I want to do HW early is to have more time to study this so I can get good grade on the next test.
 
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bump I got the current, and the length. I'm still having trouble with finding the right B*sin(phi).
 

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