Calculating Magnetic Moment of Hydrogen Atom

AI Thread Summary
The discussion focuses on calculating the magnetic moment of a hydrogen atom, with the electron moving at 0.10c and a radius of 0.5*10^-5 m. The initial calculations led to a magnetic moment of 12 A m^2, which was questioned for being too high. Participants clarified the formula for current, suggesting I = qv/(2πr) and emphasized checking units throughout the calculations. After correcting a typo and normalizing by distance, the final approach was confirmed to be accurate. The conversation highlights the importance of careful unit management and formula application in physics problems.
iontail
Messages
22
Reaction score
0

Homework Statement



find the magnetic moment of a hydrogen atom given that the election moves at 0.10c around the nucleus and the radius is 0.5*10^-5 m

Homework Equations



n/a

The Attempt at a Solution



this is what i did.

I = nev
=ev (I = current e= charge of electron, v = velocity)

m = IA (A = area)

my result is 12 A m^2.

The result looks too big...am I doing something wrong. can you please verify that my answer is right.
 
Physics news on Phys.org
iontail said:
I = nev
=ev (I = current e= charge of electron, v = velocity)
What's n?

Hint: Find the current by figuring out long it takes for the electron to orbit the nucleus.
 
Your approach is correct, you may want to check your units.

e = 1.6*10^-19 coulomb
v = 3*10^7 m/s
r = 0.5*10^-5 m

I = q v
m = I pi r^2

I get:

I = 4.8*10^-12
m = 3.77*10^-22
 
jpreed said:
I = q v
You might want to rethink that equation.
 
Doc Al said:
You might want to rethink that equation.


hi sorry about that i made a typo.
n=number of free electron

and I = nev/(r*pi*r) (r= radius of atom)

the answer i got before is still correct. I just made a typo while putting the detials in the computer.

I am just suprised that the magnetic moment for an atom is so high. CAn you please verify the answer. or tell me if i have made any other mistake.
 
iontail said:
hi sorry about that i made a typo.
n=number of free electron
OK, so n = 1.

and I = nev/(r*pi*r) (r= radius of atom)
That doesn't look right. (Check the units.)
 
Doc Al said:
OK, so n = 1.


That doesn't look right. (Check the units.)

I = ev/2*pi*r

it should be right now.
 
iontail said:
I = ev/2*pi*r

it should be right now.
Now you've got it.
 
Doc Al said:
You might want to rethink that equation.

Oops, I forgot to normalize by the distance. You are right.

It should be

I = q v / (2 pi r)
 
  • #10
jpreed said:
Oops, I forgot to normalize by the distance. You are right.

It should be


I = q v / (2 pi r)


thabk you all for you help...
 
Back
Top