Calculating Magnitude of Contact Force Between Boxes 1 & 2

AI Thread Summary
To find the magnitude of the contact force between boxes 1 and 2, it is essential to consider the total mass being accelerated by the applied force of 9.00 N. The contact force is not equal to 9.00 N because the force must account for the masses of boxes 2 and 3, which influence the acceleration of box 1. The net force acting on box 1 is derived from the total mass of boxes 2 and 3, leading to a lower contact force than initially assumed. Understanding the distribution of forces and masses is crucial for accurate calculations. The correct approach involves applying Newton's second law to find the contact force.
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Homework Statement


A force of magnitude 9.00 N pushes three boxes with masses m1 = 1.30 kg, m2 = 2.80 kg, and m3 = 4.90 kg
05-20alt.gif

Find the magnitude of the contact force between boxes 1 and 2.

Homework Equations


Fnet,x = ma?


The Attempt at a Solution


I thought that it would be 9.00 N, since the boxes are back-to-back-to-back, but that answer is wrong.
 
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BugsSport said:

Homework Statement


A force of magnitude 9.00 N pushes three boxes with masses m1 = 1.30 kg, m2 = 2.80 kg, and m3 = 4.90 kg
05-20alt.gif

Find the magnitude of the contact force between boxes 1 and 2.

Homework Equations


Fnet,x = ma?

The Attempt at a Solution


I thought that it would be 9.00 N, since the boxes are back-to-back-to-back, but that answer is wrong.

Welcome to PF.

At the interface between 1 and 2, the mass of 2 and 3 has already been accounted for by the force, so the force required to accelerate the remaining mass is given by the force that it needs to still push.

Otherwise, if that force was still the whole 9N, then applying that to the total mass left would result in an acceleration to the left that just wouldn't be there.
 
okay got it thank you
 
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