Calculating mass of particle given total energy and momentum

Click For Summary
A particle has a total energy of 10 GeV and a momentum of 6 GeV, prompting a calculation for its mass in GeV/c^2. The equations used include momentum and energy relations, leading to an expression for mass involving both energy and momentum. A participant noted a potential misunderstanding regarding the definition of "total energy," suggesting it might refer to kinetic energy. The correct mass calculation was confirmed to be 8 GeV/c^2, highlighting that the initial confusion stemmed from a calculation error. The discussion emphasizes the importance of careful calculations in particle physics.
Froskoy
Messages
26
Reaction score
0

Homework Statement


A particle, observed in a particular reference frame, has a total energy of 10GeV and a momentum of 6GeV. What is its mass in units of GeV/c^2?

Homework Equations


I used p=\gamma mv
and
E=\gamma mc^2

The Attempt at a Solution


So I divided the above equation for P by the equation for E to get

\frac{P}{E} = \frac{v}{c^2} \Rightarrow v=\frac{P}{E}c^2

and then substituting back into the quation for E:

m = \frac{E}{\gamma c^2} = \frac{\sqrt{1-\frac{P^2}{E^2}}E}{c^2}

But this doesn't give the correct answer - any ideas?

With very, very many thanks,

Froskoy.
 
Physics news on Phys.org
Hi Froskoy! :smile:

(try using the X2 button just above the Reply box :wink:)
Froskoy said:
A particle, observed in a particular reference frame, has a total energy of 10GeV and a momentum of 6GeV. What is its mass in units of GeV/c^2?

It's not clear what they mean by "total energy". :redface:

Maybe they mean the kinetic energy, (γ - 1)mc2

try that :smile:
 
You dropped a factor of c^2, in your final equation, which should read:
m = \frac{E \sqrt{1-\frac{p^2 c^2}{E^2}}}{c^2}
which is consistent with the well-known relation E^2 = p^2 c^2 + m^2 c^4. However, this shouldn't matter, since when using units of GeV and GeV/c^2, c=1 anyway. Why doesn't this give the right answer? If E= 10Gev, and p = 6GeV/c^2, m = 8Gev/c^2, which is what your equation gives.
 
Hi!

Thanks very much for confirming what I had is correct - it turned out to be a calculation error.

With very many thanks again,

Froskoy.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
46
Views
2K
Replies
13
Views
2K
Replies
4
Views
653
Replies
3
Views
2K
Replies
8
Views
3K