Calculating Maximum Height and Horizontal Range of 0.25kg Skeet

AI Thread Summary
The discussion focuses on calculating the maximum height and horizontal range of a 0.25 kg skeet shot at a 30-degree angle with an initial speed of 25 m/s, which is then hit by a 15 g pellet traveling upward at 200 m/s. The key points include determining the skeet's maximum height after the collision and calculating the additional horizontal distance it travels. The conservation of momentum is emphasized as a crucial principle to apply during the collision. Participants are encouraged to consider the equations governing projectile motion and energy conservation. The thread aims to guide users through solving the physics problem step-by-step.
wing_88
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Homework Statement


0.25-kg skeet is fred at an angle 30 to horizontal with a speed 25m/s.
when it reaches tha max. height, it is hit from below by a 15g pellet traveling verticaly upwared at speed of 200m/s. the pellet is embedded to the skeet.
1) how much higher did the skeet go up?
2) how much extra horizontal distance?


Homework Equations





The Attempt at a Solution


at highest v=0
vsin 0 is the speed of skeet
horizontal range should be v times t
..
 
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Welcome to PF!

Hi wing_88! Welcome to PF! :wink:
wing_88 said:
at highest v=0 …

Nooo. :redface:

Anyway, start by considering what is conserved at the time of collision … then what is the equation for that? :smile:
 

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