Dell
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when calculating the mean square error i have been using the differential,
if a length measured is x=2 and the error mx=+- 0.005
then x=2+-0.005
if i have x+y where y=3, my=+-0.02
mx+y=\sqrt{m<sub>y</sub><sup>2</sup>+m<sub>x</sub><sup>2</sup>}
mx*y=\sqrt{(y*m<sub>x</sub>)<sup>2</sup>+(x*m<sub>y</sub>)<sup>2</sup>}
but if i have x^2 does this work the same
for example if the area of a rectangle is x*2x can i say 2x2
m2x2=4x*mx
if a length measured is x=2 and the error mx=+- 0.005
then x=2+-0.005
if i have x+y where y=3, my=+-0.02
mx+y=\sqrt{m<sub>y</sub><sup>2</sup>+m<sub>x</sub><sup>2</sup>}
mx*y=\sqrt{(y*m<sub>x</sub>)<sup>2</sup>+(x*m<sub>y</sub>)<sup>2</sup>}
but if i have x^2 does this work the same
for example if the area of a rectangle is x*2x can i say 2x2
m2x2=4x*mx