Calculating Minimum of PT = 16.8e0.0697t + 204e-0.356t

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Calculate the minimum of PT = 16.8e0.0697t + 204e-0.356t

PT' = 0.0697 x 16.8e0.0697t + -.356 x 204e-0.356t

Stationary points occur when PT'=0. Therefore:

0=0.0697 x 16.8e0.0697t + -.356 x 204e-0.356t

My final answer was that t = 4.29. However, the Graphics Calculator begs to differ and says that it is 5.695.

Attached is my working; where have I gone wrong?
 

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Procrastinate said:
Was that using the natural logarithm or an exponent?

Up to this point you were doing well, then you decided to start dividing and made an error. Try by multiplying it out first then dividing:

0.356*204*exp(-0.356*t) = 0.0697*16.8*exp(0.0697*t)

It should be

72.624*exp(-0.356*t) = 1.17096*exp(0.0697*t)
62.020*exp(-0.356*t)=exp(0.0697*t)

62.020=exp(0.0697*t)/exp(-0.356*t)

ln(62.020)=ln(exp(0.4257*t))

4.1275 = 0.4257*t

t=9.6957
 
Last edited:
In your work, you seem to have changed 0.30 ... into 0.030... a little below the middle of the page.
 
I did that and now I get 9.695...
 
hgfalling said:
In your work, you seem to have changed 0.30 ... into 0.030... a little below the middle of the page.

I rectified that afterwards. Perhaps what I graphed into my Graphics Calculator is wrong.
 
It is. Silly me.
 
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