Calculating Minimum Power to Climb a Hill

AI Thread Summary
To calculate the minimum power required for a truck weighing 3.0 * 10^4 Newtons to climb a hill of 1.6 * 10^2 meters over a height of 8.0 * 10^2 meters in 480 seconds, the formula P = W/t is used. The confusion arises from the term "minimum," which indicates that the calculation should only consider the work done against gravity, excluding factors like friction or acceleration. The correct approach involves determining the work done against gravitational force and dividing it by the time taken. The initial answer of 1.5 * 10^5 W was incorrect, and further clarification on the calculations is needed to arrive at the correct solution. Understanding the distinction of "minimum" power is crucial for accurate calculations in physics problems.
majormuss
Messages
124
Reaction score
4

Homework Statement


A truck weighing 3.0 *10^4 Newtons was driven up a hill that is 1.6*10^2 meters long to a level area that is 8.0* 10^2 above the starting point. If the trip look 480 seconds, what was the minimum power required?


Homework Equations



P= W/t

The Attempt at a Solution


My answer was 1.5*10^5 W, but that is not part of the answers provided.The word 'minimum' confuses me a bit. Am not sure how that changes m answers.
 
Physics news on Phys.org
Please show how you arrived at your answer so we can see where you may have gone wrong. The word minimum is in there because the power could be more if you included friction or air resistance, or if the truck was accelerating. The problem is asking for the power based on the work done against gravity.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top