Calculating Molality: Solution Density and Molarity Relationship

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To calculate the molality of a 1.392 M sodium carbonate solution with a density of 1.1353 g/mL, start by determining the mass of 1 liter of the solution, which is 1135.3 grams. Next, calculate the mass of sodium carbonate in the solution using its molarity; 1.392 moles of Na2CO3 corresponds to approximately 139.2 grams. Subtract the mass of sodium carbonate from the total mass of the solution to find the mass of the solvent, which is about 996.1 grams. Finally, use the formula for molality, which is moles of solute per kilogram of solvent, to find the molality of the solution. The calculated molality will provide insight into the concentration of the sodium carbonate in the solvent.
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A 1.392 M sodium carbonate solution has a density of 1.1353 g/mL. Calculate the molality of the solution.

Attempt
1.392 M Na2CO3 = 1.392 mol Na2CO3 per 1 L solution

I can't really make sense out of this. What would be the next step?
 
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What is the definition of molality?

Assume you have 1L of the solution. What is its mass? What is the mass of dissolved sodium carbonate? What is the mass of the solvent?
 
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