Calculating Mole Fraction from Molality: Sodium Nitrate Solution Example

AI Thread Summary
The molality of a sodium nitrate solution is given as 2.14 m, leading to the calculation of the mole fraction. Assuming 1 kg of solvent, this results in 2.14 moles of NaNO3. The mole fraction is calculated using the formula: mole fraction of NaNO3 = 2.14 / [(1000/18) + 2.14], yielding a value of 0.0370. The calculation incorporates the conversion of grams of water to moles, emphasizing the importance of using an accurate molar mass for better precision. Overall, the approach and calculations are deemed correct and helpful.
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Homework Statement



The molality of an aqueous sodium nitrate solution is 2.14 m. What is the mole fraction of sodium nitrate?

Homework Equations



Molality = moles of solute / kg of solvent.

Mole fraction of A = moles of A / total number of moles (in this case, moles of solute + moles of solution).

The Attempt at a Solution



Assuming we have 1 kg of solvent, we can assume we have 2.14 moles of NaNO3.

Mole fraction of NaNO3 is therefore 2.14 / [(1000/18) + 2.14] = 0.0370.

1000/18 because 1000 grams of water is present and there are 18 grams per mole of water. The grams cancel out and yield moles of water.
 
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Looks OK. You will get slightly better result by using more accurate molar mass of water.
 
I appreciate your consideration and helpfulness!
 
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