Calculating Moles and Mass: Ca(NO3)2, Ca2+ ions, and NaCl - Homework Solutions

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The mass of one mole of Ca(NO3)2 is calculated to be 164.1 grams. For 0.05 moles of Ca(NO3)2, there are 6.022 x 10^22 Ca2+ ions, derived from multiplying the number of moles by Avogadro's number. The number of moles of NaCl in 450 grams is determined to be approximately 5.95 moles, using the molar mass of NaCl. The calculations for the first and last questions are confirmed to be correct. Understanding these concepts is essential for mastering mole calculations in chemistry.
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Homework Statement


a) What is the mass of one mole of Ca(NO3)2?
b) How many Ca2+ ions are there in 0.05 moles of Ca(NO3)2?
c) How many moles ofNaCl are there in 450 g of this substance?
(Avogadro’s number is 6.022*1023 1/mol.)


Homework Equations



The Attempt at a Solution


a)
m=n*M=1*164.1
m=164.1g
b)
I have NO IDEA, help me
c)
n=450/75.53
n=5.95mol
 
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You see the mole ratio directly in the molecular formula. Now instead of having 1 mole of Ca(NO3)2, you have only 0.05 moles. So how many of Ca+2?
 
0.05*6.022*E23?
first and last question are true ?
 
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