Calculating Moment About Axis AC for a Given Force Vector

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To calculate the moment about axis AC for the force vector F=<7,12,-6>, the unit vector Uac is determined to be <0.8, 0.6, 0>. The cross product of Rab=<4,3,-2> and F results in Rab X F=<6,-10,0>. The moment about AC is calculated as MomentAC=4.8-6, yielding a value of -1.2. The final moment vector is expressed as MomentAC*Uac=<-.96,-.72,0>.
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Homework Statement


http://session.masteringengineering.com/problemAsset/1127287/7/Probs._454_55.jpg
Find the moment about the axis AC. F=<7,12,-6>


Homework Equations


MomentAC = Uac dotted with (Rab X F)
Uac is the unit vector from a to c


The Attempt at a Solution


Uac=<.8,.6,0>
Rab=<4,3,-2>
F=<7,12,-6>
Rab X F =<6,-10,0>
MomentAC=4.8-6
=-1.2
MomentAC*Uac=<-.96,-.72,0>
 
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