Calculating Moment of Force Produced at Point A

AI Thread Summary
To determine the moment produced by a force F of 200 lb about point A for a lamp post, the calculation involves using the formula MA = Fd, where d is the distance from A to B (20 ft). The user initially calculated the moment as 1035.3 ft-lb by using the cosine of the angle (75°) between the force and the moment arm. However, they acknowledged a misunderstanding regarding the correct application of angles and the perpendicular component of the moment arm. The discussion highlights confusion over the angles involved, particularly the relationship between the force direction and the moment arm. Clarifying these angles is essential for accurately calculating the moment of force.
musicmar
Messages
95
Reaction score
0

Homework Statement


In order to raise the lamp post from the position shown, force F is applied to the cable. If F = 200 lb, determine the moment produced by F about point A. I've attached the diagram. I apologize for the terrible quality. The length of the post from A to B is 20 ft.


The Attempt at a Solution



MA=Fd
=200 lb (cos 75) (20 ft) = 1035.3 ft-lb

I think I somehow reasoned that the angle between AB and AC is 15°, so its complement is 75°. I said that the component of the force acting perpendicular to the moment arm is 200 cos 75. I know this is backwards from what it is supposed to be. It should be the force times the perpendicular component of the moment arm. I'm not sure that it matters much here, but I don't know how to describe the perpendicular moment arm.


Thank you.
 

Attachments

  • IMG00082-20110203-2253.jpg
    IMG00082-20110203-2253.jpg
    21.1 KB · Views: 523
Physics news on Phys.org
musicmar said:
I think I somehow reasoned that the angle between AB and AC is 15°, so its complement is 75°.

Total angle is 180 degree not 90 degree
 
I meant between F and an imaginary line perpendicular to the post at B, so the angle there would be 75 degrees. I don't think that's where my mistake is. If anything, it's what these angles mean.
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top