Calculating Moment of Inertia Homework: Soccer Ball

AI Thread Summary
The discussion revolves around calculating the moment of inertia (κ) for a soccer ball rolling down a ramp. The initial parameters provided include mass, radius, time, distance, and height. The calculations involve using energy conservation principles, leading to derived equations for velocity and κ. A significant point raised is the discrepancy in the calculated time, which seemed excessively long compared to expectations. Ultimately, the user resolved the issue by correcting the units in their calculations, successfully obtaining the correct κ value.
Shawkify
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Homework Statement


An object rolls down a ramp starting from rest, demonstrate symbolically the calculation needed to go from time given to a measured κ value here. Pick your favourite object and perform the calculation.
d, m, R, t, h are known
http://puu.sh/luare/10352d0479.png

Soccer Ball:
m = 331.2 kg
R = 10.54 cm
t = 2.25 s
d = 0.2805 m
h = 0.0445 m

Homework Equations


Derived from an earlier problem:
a = (g*h)/(d*(1+k))
d = 1/2*a*Δt2

KEtotal = 1/2*m*v2 + 1/2*I*ω2
I = κ*m*R2
U = m*g*h
v = v0 + a*t

The Attempt at a Solution



Ui = KEf
m*g*h = 1/2*m*v2 + 1/2*I*ω2
m*g*h = 1/2*m*v2 + 1/2*κ*m*R2*(v/R)2
g*h = 1/2*v2 + 1/2*κ*v2
κ = (g*h)/v2 - 1
v = (g*h)/(d*(1+k))*t

Solving a system of equations gives me:
v = (2*d)/t
κ = (g*h*t2 - 2*d2)/(2*d2)

Plugging in values gives me v = 1.65 m/s and k = 30.8. Compared to a chart which gives a value of κ = 2/3 for a thin spherical shell, my κ value is extremely large.
 
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Shawkify said:
g*h = 1/2*v2 + 1/2*κ*v2
κ = (g*h)/v2 - 1
You lost a factor of 2 there, but it reappeared later.
Shawkify said:
t = 2.25 s
That seems like a very long time, given the set-up. It should be more like 0.6 s.
Shawkify said:
v = (2*d)/t
gives me v = 1.65 m/s
How do you get that from these numbers? (2*0.2805)/2.25=0.25
 
haruspex said:
You lost a factor of 2 there, but it reappeared later.

That seems like a very long time, given the set-up. It should be more like 0.6 s.

How do you get that from these numbers? (2*0.2805)/2.25=0.25

Thanks for your help, I've been told the units for this problem were all messed up and have successfully solved the corrected version.
 
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