Calculating momentum of soccer ball.

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The momentum of a soccer ball kicked at +26.8 m/s with a mass of 0.425 kg is calculated to be 11.4 kg·m/s. The change in momentum is also 11.4 kg·m/s, as it starts from rest, confirming that the change in momentum equals the impulse imparted to the ball. The discussion clarifies that while the numerical values for change in momentum and impulse are the same, they are expressed in different contexts. The correct units for impulse should be Newton-seconds (N·s), not N/S, as the latter is incorrect for this application. Understanding the relationship between momentum and impulse is crucial for solving related physics problems accurately.
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Homework Statement


A soccer player, kicking a soccer ball, gives the ball a velocity of +26.8 m/s. The mass of the ball is 0.425 kg, and the duration of the impact is 1.05  10–3 s.

a) What is the momentum of the soccer ball after it has been hit?

b) What is the change in momentum of the ball?

c) What is the impulse imparted to the ball?

Homework Equations


P = mv
(F*t)=P = mvf = mvi[/B]

The Attempt at a Solution



a) p = mv
p = (0.425kg)(26.8m/s)
p = 11.4 kg(m/s)

b) (F*t)=P = mvf = mvi
= (0.425)(26.8) - (0.425)(0m/s)


c) this questions makes me unpleasant, I thought the change in momentum is same as impulse imparted to the ball. What's the difference between b) and c) ?
 
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a) p = mv
p = (0.425kg)(26.8m/s)
p = 11.4 kg(m/s)
... so far so good: you should check your assumptions for the next bit...
b) (F*t)=P = mvf = mvi
= (0.425)(26.8) - (0.425)(0m/s)
... this answer is not finished.
You know the initial momentum is 0 and the final momentum is p (your label above) so the change in momentum must be p ##\Delta p = 11.4##kgm/s

I thought the change in momentum is same as impulse imparted to the ball.
That is correct.
What's the difference between b) and c) ?
What makes you think there should a difference?
Sometimes there is more than one way of saying the same thing, and the teacher want's to test that you understand this.

You can finesse the answer by working out the average force imparted to the ball too.
 
Simon Bridge said:
... so far so good: you should check your assumptions for the next bit...
... this answer is not finished.
You know the initial momentum is 0 and the final momentum is p (your label above) so the change in momentum must be p ##\Delta p = 11.4##kgm/s

That is correct. What makes you think there should a difference?
Sometimes there is more than one way of saying the same thing, and the teacher want's to test that you understand this.

You can finesse the answer by working out the average force imparted to the ball too.

Oops for b) it is same as the answer from a) but in different units 11.4 N/S

I will find more info about the difference between those two.
 
Notes:
Oops for b) it is same as the answer from a) but in different units 11.4 N/S
N/S is not the correct SI units for change in momentum or for specific impulse - you want N.s
Impuse is force times time ... so Newtons times seconds. "Seconds" is lowers case "s".
Upper case "S" is the SI symbol for the "siemen" - the unit of electrical conductance.

N.s are the same units as kg.m/s - the "N" stands for "kg.m/s2".
This should make sense because change in momentum should really be in momentum units just like change in time is in time units and change in length is in length units.

See also: http://www.periodni.com/international_system_of_units.html
 
Glenboro said:
d
Simon Bridge said:
Notes:
N/S is not the correct SI units for change in momentum or for specific impulse - you want N.s
Impuse is force times time ... so Newtons times seconds. "Seconds" is lowers case "s".
Upper case "S" is the SI symbol for the "siemen" - the unit of electrical conductance.

N.s are the same units as kg.m/s - the "N" stands for "kg.m/s2".
This should make sense because change in momentum should really be in momentum units just like change in time is in time units and change in length is in length units.

See also: http://www.periodni.com/international_system_of_units.html
I usually write down units correctly, but I often make an error when I'm typing into computer :P However, I will definitely check that website as it contains a lot of useful physics.
 
There's often a mark (in exams) associated with getting the right units so it's worth taking some time over.
The answers for all three are basically the same number with the same units ... only the context has changed.
 
Simon Bridge said:
There's often a mark (in exams) associated with getting the right units so it's worth taking some time over.
The answers for all three are basically the same number with the same units ... only the context has changed.
Yup, I
Simon Bridge said:
There's often a mark (in exams) associated with getting the right units so it's worth taking some time over.
The answers for all three are basically the same number with the same units ... only the context has changed.
Thanks you for help, advice sir
 

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