Calculating Multiple Images in a Plane Mirror

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SUMMARY

The discussion focuses on calculating the distances of multiple images produced by two plane mirrors positioned on opposite walls. When a person stands 5 feet from the left mirror and 10 feet from the right mirror, the first image in the left mirror is located 10 feet behind it. The second image is calculated to be 30 feet away, and the third image is 40 feet away, based on the distances and the arrangement of the mirrors.

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  • Understanding of geometric optics principles
  • Familiarity with the concept of virtual images in plane mirrors
  • Basic skills in distance measurement and spatial reasoning
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vu95112
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Plane Mirror
A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror when the person is 5ft from the mirror on the left wall and 10 ft from the mirror on the right wall.

I know the first image is 10 ft because in the plane mirror, the image is as far behind the mirror as the object is in front. I don’t know how to figure out the second and the third images? I need you help please. Thank you.

Vu95112
 
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Try making a diagram like that found in scrolling down the page at http://dev.physicslab.org/Document.aspx?doctype=3&filename=GeometricOptics_PlaneMirrors.xml":

It may help to keep you from getting confused. The first image in the left mirror is the virtual image of the person and as you say 10' behind the mirror. Apply the same logic to the first image in the right mirror. It would be 5' behind the mirror and since the mirrors are 15' apart, would seem to be 20' away. And so forth.
 
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Hello denverdoc,
Thank you very much for your help. A diagram is very useful.
The first image is 10ft
The second image is 30 ft
The third image is 40 ft

Thank you,

Vu95112
 

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