Calculating Net Displacement: East and North Components in a 50-70-20 Triangle"

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To calculate the net displacement after walking 50 meters Northeast, 70 meters West, and 20 meters South, the angle for the Northeast direction is 45 degrees. The East component can be found using the cosine of 45 degrees, while the North component uses the sine of 45 degrees. A sketch can help visualize the vectors and their placement, aiding in determining the net displacement vector. The net displacement involves summing the x (East-West) and y (North-South) components, resulting in a net vector that may yield a West and North component rather than strictly East and North. Understanding these calculations is crucial for accurately determining the net displacement.
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Homework Statement


Suppose someone walks 50 meters Northeast, then turns West and walks for 70 meters, and finally turns South and walks 20 meters. What is their East and North components of the net displacement.


Homework Equations



If I knew one, I could probably figure this one out.

The Attempt at a Solution



Tried using /A/= 50cos(x) for East component and /A/= 50 sin(x) and also plugged in the estimated angle for x as well. I don't know if I'm just overlooking something or just not understanding the question or even if I know what I'm doing.

Any help will be much appreciated.
 
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sydneyfranke said:

Homework Statement


Suppose someone walks 50 meters Northeast, then turns West and walks for 70 meters, and finally turns South and walks 20 meters. What is their East and North components of the net displacement.
Tried using /A/= 50cos(x) for East component and /A/= 50 sin(x) and also plugged in the estimated angle for x as well. I don't know if I'm just overlooking something or just not understanding the question or even if I know what I'm doing.

Any help will be much appreciated.
Why do you say x is an estimated angle. If someone is walking Northeast, the angle with the horizontal is exactly 45 degrees. Try drawing a sketch to scale , placing the tail of the 2nd vector on the arrow of the first vector, then the tail of the third vector on the arrow of the 2nd vector. The net displacemnt is the vetor pointing from the origin to the arrow of the third vector. That will give you a rough idea of the net displacemnt vector. Analytically, sum all x components to get the x component of the net vector, and sum y components to get the y component of the net vector. But i don't get an east and north component of the net displacemnt, i get a west and north component.
 
Thanks
 
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