Calculating Object-Lens Distance for Diverging Lens Optics

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SUMMARY

The discussion focuses on calculating the object-lens distance for a diverging lens with a focal length of -6mm and an image magnification of 0.5. The user initially calculated the distance as 18mm using the lens maker formula and the magnification ratio but arrived at an incorrect conclusion. The correct object-lens distance is 6mm, as confirmed by user ehild, who provided the necessary corrections and guidance on sign conventions in the calculations.

PREREQUISITES
  • Understanding of lens formulas, specifically for diverging lenses
  • Knowledge of magnification ratios in optics
  • Familiarity with sign conventions in optical calculations
  • Basic proficiency in algebra for solving equations
NEXT STEPS
  • Study the lens maker's formula for diverging lenses
  • Learn about sign conventions in optics and their implications
  • Explore practical applications of magnification in optical systems
  • Practice solving problems involving object and image distances in lens systems
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Students of optics, physics educators, and anyone involved in optical engineering or lens design will benefit from this discussion.

slaw155
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Diverging lens has focal length 6mm and image magnification 0.5. What is the distance between object and lens?

I used the fact that distance image to lens/distance object to lens = 0.5 and the lens maker formula with f=-6 and combined the two formula but this gives distance = 18mm, when answer is in fact 6mm.
Where have I gone wrong?
 
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slaw155 said:
Diverging lens has focal length 6mm and image magnification 0.5. What is the distance between object and lens?

I used the fact that distance image to lens/distance object to lens = 0.5 and the lens maker formula with f=-6 and combined the two formula but this gives distance = 18mm, when answer is in fact 6mm.
Where have I gone wrong?

Show your work. Take care of the signs.

ehild
 
thanks solved it
 

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