Calculating Object Location for Converging Lens with M=-1

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    Converging Lens
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For a converging lens with a focal length f and a magnification of -1, the object must be placed at a distance of 2f from the lens. The relationship between object distance (S) and image distance (S') is defined by the magnification formula, where S = S' when magnification is -1. The discussion highlights that placing the object at 2F results in an inverted, real image of the same size. Additionally, the lens equation can be utilized to confirm this relationship without relying on predefined cases. Understanding these principles is essential for solving similar optical problems.
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Homework Statement


" A converging lens has a focal length f. The object location at magnification equal to -1 is? "

Homework Equations


m = -S'/S

The Attempt at a Solution


Here is my solution:

M= -1 , S=??
M= -S'/S
-1 = -S'/S
S= -S'/-1
S=S'
And from case 2 that says if an object is placed at 2F the image will be inverted, real , and have the same size as the object.
And from the last sentence ( backed up with my conclusion of S=S' ) the object is placed at 2F.
Is my answer correct?
 
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Your answer is correct if by 2F you mean the object should be placed at a distance 2f from the lens, where f is the focal length of the lens. The symbol F is usually used to label a focal point, so 2F doesn't have much meaning.

I'm not familiar with the "case 2" statement which apparently gives the answer immediately.

For practice, see if you can get the answer without "case 2". Use the lens equation 1/S + 1/S' = 1/f for the case where S = S'.
 
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