Calculating Oil Flow Speed: Density 850 kgm^3, Pipe Diameter 8 cm

AI Thread Summary
To calculate the speed of oil flowing through a pipe with a density of 850 kg/m^3 and a diameter of 8 cm at a rate of 9.5 liters per second, the formula used is v_1 = (dv/dt)/a_1. The flow rate of 9.5 liters per second is converted to cubic meters per second by multiplying by 10^-3. The cross-sectional area of the pipe is calculated using the formula for the area of a circle, resulting in a speed of 1.9 m/s for the oil. Understanding the conversion from liters to cubic meters is essential for accurate calculations. The discussion clarifies the importance of unit conversion in fluid dynamics.
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Homework Statement


oil w/ density of 850 kgm^3 goes through a pipe diameter 8 cm at a rate of 9.5 liters / s.
what is the speed of the oil?


Homework Equations



v_1 = (dv/dt)/a_1 = (9.5*10^-3)/(pi(.04)^2) = 1.9 m/s

The Attempt at a Solution



i have the solution because this problem was given to me. I just don't understand where the 10^-3 came from and how it was derived.
 
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ssb said:
I just don't understand where the 10^-3 came from


It comes from converting the volume from litres into m^3.
 

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