Calculating Output of Solar Cells in KWH

AI Thread Summary
To calculate the output of solar cells in kWh, the formula used is Kilowatts = (Amperes * Volts) / 1000. In this case, with two 6-volt solar panels producing a combined current of 5.263 mA, the output is calculated as 0.000094734 kWh. However, there is confusion regarding the inclusion of bulb voltages in the calculation, as the focus should be solely on the solar panels' output. It's important to use standard SI units and to note that the voltage may drop under load conditions. Accurate calculations should disregard the bulbs to avoid misrepresentation of the solar cells' power generation.
assuc
Messages
3
Reaction score
0
hi,
I am working on a small solar cell project for which i bought two small solar cells panels of 6volt each producing current of 5.263milli ampere in combination.
I want to know that how can i calculate the values of solar cells output in kwh, on the output i have placed two bulbs of 3 volts in series and connected solar cells in parallel so as to increase the current.
Or any other method of calculating values and please recommend a graphical value too.
All answers will be highly appreciated.
 
Physics news on Phys.org
I'm relatively new to physics, (17 going to college physics next year), but I believe you have everything you need to understand the output in Kilowatts per hour.

Kilowatts= (Amperes * Volts)/1000

Kw= (.005263 * 18)/1000

Kw= .000094734

^here above i converted the milli amperes into regular amperes then combined the voltages of both the 6 volt solar panels and the two 3 volt bulb. Then to top it off, I divided by 1000 for converting watts into kilowatts. Then for kilowatts to kilowatts per hour, multiply by 1 hr and you still get the same number as an output, or .000094734KwH.

That's for the combined system I assumed you wanted, otherwise you wouldn't have needed the bulbs.

Again, I'm VERY new to just physics in general, but I try to help since there are no replies yet :/ And I just did basic equations...
 
physicsofme said:
I'm relatively new to physics, (17 going to college physics next year), but I believe you have everything you need to understand the output in Kilowatts per hour.

Kilowatts= (Amperes * Volts)/1000

Kw= (.005263 * 18)/1000

Kw= .000094734

^here above i converted the milli amperes into regular amperes then combined the voltages of both the 6 volt solar panels and the two 3 volt bulb. Then to top it off, I divided by 1000 for converting watts into kilowatts. Then for kilowatts to kilowatts per hour, multiply by 1 hr and you still get the same number as an output, or .000094734KwH.

That's for the combined system I assumed you wanted, otherwise you wouldn't have needed the bulbs.

Again, I'm VERY new to just physics in general, but I try to help since there are no replies yet :/ And I just did basic equations...

I really appreciate your answer...!
But the confusion is that you have combined the output voltage of each bulb while taking out the kilowatts... as i am only concerned about the power solar cells are producing not the bulbs, as to best of my knowledge we will multiply the voltage value of solar cells and that will be 6Volts (as both solar panels are in parallel so the voltage remains same in parallel combination).
Do correct me if i am wrong.!
thanks again
 
just a couple of comments :)

@ physicsofme...
always use the standard SI units when doing formula, do any conversions at the end
so always use W = V * A etc, else you may get into strife with more complex calculations :)

Also, your globe voltages should NOT have been included, that's giving false info.
As assuc said its the power generated by the panels that is being calculated. The globes are not supplying voltage to the system, in your calc they incorrectly are.


@assuc...
The 6V and 5.263 mA is probably the open circuit (no load) ratings. Under load, the output voltage is going to drop a volt or so. check the paper work for the panel and see if it comments on no load and loaded ratings :)


cheers
Dave
 
Last edited:
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Back
Top