Calculating Potential and Kinetic Energy for Objects in Motion

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The discussion focuses on calculating potential and kinetic energy for various scenarios involving objects in motion. An elevator carrying a man is analyzed, revealing it ascends approximately 149.64 meters based on the power developed. A collision between a moving car and a parked car is examined, showing that after impact, the combined mass travels at 101.875 km/h with a kinetic energy of 8,302,812 J. Additionally, the potential and kinetic energies of a 500-gram ball are calculated at different heights, confirming the values for each state. The importance of unit accuracy in calculations is emphasized throughout the discussion.
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1. A 2150-kg elevator carries a 90-kg man from the ground up to the top floor of a building in 45 seconds. In doing so, the elevator develops 73000 W of power. How high was the man carried?

(73000 W) (45 s) = 3285 kJ
(9.8 m/s ^2) (2240 kg) = 21952 N

3285 kJ / 21952 N = 149.64 m



2. A 600-kg car traveling at 163 km/hr collides head-on with a 1000-kg parked car. If the cars stick together after impact, how fast are they then traveling? What is their kinetic energy?

(1000 kg) (163 km/h) = (600 kg + 1000 kg) (101.875 km/h)
½ (1600 kg) (101.875) = 8302812 J





3. A 500-g ball rest on top of a tower, 15 meters tall. Calculate its potential and kinetic energies a) when the ball rests on top of the tower, b) after the ball has fallen 10 meters toward the ground, c) 1 meter above the ground.

a. KE = 0
PE = (.5 kg) (9.8 m/s^2) (15 m)
PE = 73.5 J

b. KE = ½ (.5 kg) (196 m/s)
KE = 49 J
PE = (.5 kg) (9.8 m/s^2) (5 m)
PE = 24.5 J

c. KE = ½ (.5 kg) (274.4 m/s)
KE = 68.6 J
PE = (.5 kg) (9.8 m/s^2) (1 m)
PE = 4.9 J
 
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The numbers appear to be ok.

You need to be more careful with your units

KE = ½ (.5 kg) (196 m/s)
Should read

KE = ½ (.5 kg) (196 (m/s)2)
 
seems ok to me...

marlon
 
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