Calculating Potential Energy in a Parallel Plate Capacitor

AI Thread Summary
To calculate the potential energy in a parallel plate capacitor with a point charge, the relevant equations include V = w/q and w = 1/2cv^2. The charge of 6.62 µC and mass of 0.0788 kg are suspended at an angle of 23.7 degrees between the plates, which are separated by 0.0242 m. The force acting on the charge can be calculated using Coulomb's law, F = k * q1 * q2 / r. The discussion emphasizes the need for a diagram to visualize the setup, as the length of the pendulum is not provided, complicating the calculations.
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Homework Statement



A point charge mass of 0.0788kg and q charge= +6.62 uc is supended by a thread between the vertical plates of a parallege capacitor. If the angle of delflectionis 23.7 degress and the separation between the plates is d= 0.0242m, what's the potential energy?

Homework Equations


v=w/q


The Attempt at a Solution


not sure, where to begin but...
V= w/q
w=1/2cv sq
F= keqq/r
F= 8.99e9 (6.62e-6)/.0242 sq
 
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I think you'll need to draw a picture here.
 


i have 2 parallel lines then the distance btw the lines is d= .0242, then a pendulum ball @ an angle
 


xswtxoj said:
i have 2 parallel lines then the distance btw the lines is d= .0242, then a pendulum ball @ an angle

What's the length of the pendulum?
 


there isn't it only tells u the angle and the distances btw the 2 parallel lines
 
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