Calculating Power of Waterfall: PE, Work, & Electricity

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The discussion focuses on calculating the potential energy (PE) of a waterfall that is 30 meters high with a flow of 10,000 kg of water per second, resulting in a PE of 2.94 million joules. It then attempts to calculate the power delivered if all potential energy is converted to work, leading to a force of 98,000 Newtons and a work output of 980 megajoules. A participant questions the accuracy of the power calculation, emphasizing the need to consider the physical dimensions when multiplying force by mass, as it should reflect energy per second, equating to power. The correct approach suggests that the energy can be used to power 100-watt light bulbs, with the calculation indicating how many bulbs can be lit. The discussion highlights the importance of understanding the relationship between energy, power, and practical applications in electricity generation.
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a waterfall is 30 m high and 10000 kg of water flow over it every second
A) calculate the potential energy
PE = mgh
got 2.94E6 joules

B) calculate the power delevered by the water of all the potential energy is converted to work

F = mA
F= 10000 * 9.80
f = 98000

w = Fm
w 98000 * 10000
w = 980 MJ mega joules

C)If all the power were converted to electricity, how many 100watt light bulbs could be lit

not even sure on how to approach this
[?]
 
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B is WRONG Look at the physicsl dimensions when u multiply force by mass is it Energy
 
Look the energy mgh which u calulated is per second
which is power itself

with this energy u can lit mgh/100 bulbs

hope u will get now
 
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