Calculating Power: Torque on a 20 Kg Rod Pivoted at 6m | 500 Rad Rotation

  • Thread starter Thread starter b577phaty
  • Start date Start date
  • Tags Tags
    Rod Torque
AI Thread Summary
To calculate the average power exerted by the motor on a 20 kg rod pivoted at its center, use the formula for power, P = τ * ω, where τ is torque and ω is angular velocity. The average power can be determined by finding the angular displacement and time taken for the rotation. For instantaneous power, calculate the angular velocity at the specific angle of 500 rad and apply the same power formula. The torque applied is 2400 Nm, which is crucial for both calculations. Understanding these formulas and their application is essential for solving the problem effectively.
b577phaty
Messages
4
Reaction score
0
A 20 Kg slender rod pivoted at its center has a length of 6 m. A motor applied a torque of 2400 Nm on the rod to turn it from rest.
(a) Find the average power by the motor when the rod rotates an angle of 500 rad. _____________________
(b) Find the instantaneous power of the motor at the moment that the rod rotates an angle of 500 rad. ______________________

I am unsure how to start this.
 
Physics news on Phys.org
You should at least list some formulas you think you might need. For example, a formula for power at least.
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Uniform rotating rod about a point at one end of the rod
Replies
3
Views
2K
Rotating rod of negligible mass attached to two point masses
Replies
19
Views
4K
How Does Torque Apply to a Rotating Rod on a Frictionless Surface?
Replies
4
Views
2K
Rod w/ Pivot and Attached Mass Pendulum
Replies
4
Views
2K
Simulating a Rotary Inverted Pendulum in Python
Replies
15
Views
1K
Calculating Angular Speed of Rotating Apparatus with Attached Mass and Rod
Replies
1
Views
2K
Rod swinging and hitting a ball
Replies
31
Views
4K
Rotational Motion Question, lever arm with two masses
Replies
2
Views
2K
Rod rotating about pivot with spring
Replies
4
Views
8K
Rotational motion magnitude question -- Rod mounted on a pivot
Replies
11
Views
6K

Hot Threads

Recent Insights

Back
Top