Calculating Projectile Drop Distance for Supply Plane Delivery

AI Thread Summary
To calculate the drop distance for a supply plane delivering food to scientists on a glacier, the plane's altitude is 116m and it travels at 170m/s. The problem involves using kinematic equations to determine how far short of the target the package should be dropped. By assuming the plane flies horizontally, the time of fall was calculated to be approximately 4.863 seconds. Using this time, the horizontal distance to drop the package was found to be about 826.71 meters. This approach effectively applies principles of projectile motion to solve the problem.
aligass2004
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Homework Statement


A supply plane needs to drops a package of food to scientists working on a glacier in Greenland. The plane flies 116m above the glacier at a speeds of 170m/s. How far short of the target should it drop the package?


Homework Equations


Kinematic equations


The Attempt at a Solution


As with my other two posts, I know what I need to find. I just don't know how to go about finding it. I'm so confused about finding the components of the velocity without a given angle.
 
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aligass2004 said:

Homework Statement


A supply plane needs to drops a package of food to scientists working on a glacier in Greenland. The plane flies 116m above the glacier at a speeds of 170m/s. How far short of the target should it drop the package?


Homework Equations


Kinematic equations


The Attempt at a Solution


As with my other two posts, I know what I need to find. I just don't know how to go about finding it. I'm so confused about finding the components of the velocity without a given angle.
assume it's flying horizontally, since no other info is given.
 
I want to say that this problem is like the other one you helped me with, but I don't think that's the case.
 
aligass2004 said:
I want to say that this problem is like the other one you helped me with, but I don't think that's the case.
well, its kind of like the same, xcept in the other one, you were given x and v_x, you solved for t, then found the height. In this one, you are given h and v_y, solve for t, then find x. Sort of like the other one in reverse.
 
Ok, I used what I did in the other problem I had. You didn't help on that one. I solved for t using Yf = Yi + Vyi(t) - 1/2 g(t^2). I got 4.863s. Then I used Xf = Xi + Vx(t) to find x, which I got to be 826.71. Thank you again!
 
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