Calculating Q such that E(0,0,0)=0

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SUMMARY

The discussion focuses on calculating the electric field at the origin due to a half ring of charge, specifically determining the conditions under which E(0,0,0) equals zero. The relevant equation presented is the integral expression for the electric field contribution from the half ring, given by 1/(4 π ε0) ∫0π (ρ r sin(θ) dθ) / r2, where r represents the radius and ρ denotes the line density of charge. The radial components cancel out due to symmetry, leaving only the vertical component contributing to the electric field.

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Homework Statement
Attached below.
Relevant Equations
Attached below.
Question

1636907568790.png

Relevant equation;
gif.gif

My attempt:
%5C%5C%20Solve%5C%3Bfor%5C%3BQ%20%5C%5C%5C%5CQ%3D2.gif


Could someone please confirm my answer?
 
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Electric field at the Origin contributed from half ring is of direction - y and its magnitude is expressed by integral
\frac{1}{4 \pi \epsilon_0} \int_0^\pi \frac{\rho r \sin\theta d\theta }{r^2}
where r is radius of half ring, ##\rho## is line density of its charge.
 
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The component radial is cancel out, because of all direction of component radial around circle center
 

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