Calculating radius from volume

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To calculate the radius from a given volume of 20 liters using the formula V = π * 4 * r^3, the volume must first be converted to cubic meters, resulting in 0.02 m³. Rearranging the equation gives r = (V / (π * 4))^(1/3), which leads to a radius of approximately 0.11675 m. Users discussed the importance of understanding the rearrangement of equations and the use of calculators for cube roots. Clarifications were provided on how to perform calculations, particularly in using the cube root function. The discussion emphasizes the value of guiding others to understand the problem-solving process rather than simply providing answers.
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Hi all,

i am working through some worked examples for my course and there seems to be a step missing.

the step says

"the internal diameter of the vessel can be determined from"

V=PI*r^2*4r

Now all I am given is that the volume V is 20 litres. is there any way i can determine the radius from this?

The answer written is r=0.117m

Thanks for any help guys!
 
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Assuming the vessel is filled with water, do you know how many litres of water is in a cubic metre? Or how many ml makes up a cubic centimetre?
From there you need to be able to rearrange this equation to solve for r in terms of V
 
if I say x^3 = 8, is it ok to say x = 2
This problem is just like the one above

V = PI * 4 * r^3

or r^3 = V / ( PI * 4)

so r = ( V / (PI * 4) )^(1/3)

Another this to remember is V is given in liters so you have to convert it into m^3.
20 liters = .02 m^3

and if you plug the above equation in a calculator, you get r = 0.11675m

hope it helps
 
Or you could just answer the entire question...
Is it not better to give a few hints, so that the OP will understand how to do it themselves?
 
Ahh i forgot the like terms of the r^2 and r!
i can not seem to get it to work on my calculator.
I get for (V/Pi*4)) = 0.02/Pi*4 = 1.59*10-3
How do i use ^(1/3)?
Is it the abc function?
 
^(1/3) just means cube root, so is there a button with a 3 in a square root sign?
 
yeah got it just. thanks mate. That was just the front end of the question. the rest is straight forward just got hung up on the rearrangment side of it. i was close but not close enough!
 
Glad to help
 
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